Задача Задача №3546200
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Solve sin^2 x + 5 sin x − 6 = 0.
- Let t = sin x. Then t^2 + 5t − 6 = 0.
- Factor: (t + 6)(t − 1) = 0 → t = 1 or t = −6.
- Since |sin x| ≤ 1, t = −6 is impossible. So sin x = 1.
General solution:
- x = π/2 + 2kπ, where k ∈ Z.
If you want solutions in [0, 2π):
- x = π/2.