1(1/2+2)*4/3+8(7/1-4)

Task: 1(1/2+2)*4/3+8(7/1-4)

Solution (for 6th grade, explained step by step):

• Rule to follow: Do parentheses first, then multiplications/divisions from left to right, then additions/subtractions.

1. Evaluate inside the first parentheses:

   • 1/2 + 2
   • Convert 2 to a fraction with denominator 2: 2 = 4/2
   • 1/2 + 4/2 = 5/2 So, (1/2 + 2) = 5/2.

2. Multiply the first part:

   • We have 1 * (5/2) * 4/3
   • 1 * (5/2) = 5/2
   • (5/2) * (4/3) = 20/6
   • Simplify 20/6 by dividing numerator and denominator by 2: 20/6 = 10/3 So the first big term equals 10/3.

3. Evaluate inside the second parentheses:

   • 7/1 - 4
   • 7/1 is 7, and 4 is 4/1, so 7 - 4 = 3 So (7/1 - 4) = 3.

4. Multiply the second part:

   • 8 * 3 = 24 So the second big term equals 24.

5. Add the two parts:

   • 10/3 + 24
   • Write 24 as a fraction with denominator 3: 24 = 72/3
   • 10/3 + 72/3 = 82/3

6. Final answer (optional to convert):

   • 82/3 is the improper fraction.
   • As a mixed number: 82 ÷ 3 = 27 remainder 1, so 27 1/3.
   • As a decimal: 82/3 ≈ 27.333...

Ответ: 82/3 (или 27 1/3)