1(1/2+2)*4/3+8(7/1-4)

Task: 1(1/2+2)*4/3+8(7/1-4) Solution (for 6th grade, explained step by step): - Rule to follow: Do parentheses first, then multiplications/divisions from left to right, then additions/subtractions. 1) Evaluate inside the first parentheses: - 1/2 + 2 - Convert 2 to a fraction with denominator 2: 2 = 4/2 - 1/2 + 4/2 = 5/2 So, (1/2 + 2) = 5/2. 2) Multiply the first part: - We have 1 * (5/2) * 4/3 - 1 * (5/2) = 5/2 - (5/2) * (4/3) = 20/6 - Simplify 20/6 by dividing numerator and denominator by 2: 20/6 = 10/3 So the first big term equals 10/3. 3) Evaluate inside the second parentheses: - 7/1 - 4 - 7/1 is 7, and 4 is 4/1, so 7 - 4 = 3 So (7/1 - 4) = 3. 4) Multiply the second part: - 8 * 3 = 24 So the second big term equals 24. 5) Add the two parts: - 10/3 + 24 - Write 24 as a fraction with denominator 3: 24 = 72/3 - 10/3 + 72/3 = 82/3 6) Final answer (optional to convert): - 82/3 is the improper fraction. - As a mixed number: 82 ÷ 3 = 27 remainder 1, so 27 1/3. - As a decimal: 82/3 ≈ 27.333... Ответ: 82/3 (или 27 1/3)