Y=(x+2)^2-9

Here’s a quick, exam-ready breakdown of y = (x + 2)^2 − 9. - Form: Vertex form of a parabola - Vertex: (-2, -9) - Axis of symmetry: x = -2 - Opens: Upward - Vertex form interpretation: base parabola y = x^2 shifted left 2 units and down 9 units - Standard form: y = x^2 + 4x - 5 - This comes from expanding: (x + 2)^2 - 9 = x^2 + 4x - 5 - Factorized form: y = (x + 5)(x − 1) - Zeros (x-intercepts): x = -5 and x = 1 - Points: (-5, 0) and (1, 0) - y-intercept: y(0) = -5 → (0, -5) - Domain and Range: - Domain: all real numbers - Range: y ≥ -9 If you’d like, I can graph it, or help with a specific task (e.g., finding area under a portion, solving an equation with this parabola, etc.).