Задача Задача №3555924
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Compute the expression:
- sqrt(300) = 10√3, sqrt(75) = 5√3.
- So: sqrt(300) cos^2(19π/12) - sqrt(75) = 10√3 cos^2(19π/12) - 5√3
- Factor: = 5√3 [2 cos^2(19π/12) - 1] = 5√3 cos(2 · 19π/12) = 5√3 cos(19π/6)
Now cos(19π/6) = cos(3π + π/6) = -cos(π/6) = -√3/2.
Thus: 5√3 * (-√3/2) = -5 * 3 / 2 = -15/2.
Answer: -15/2.