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Задача Задача №35566
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Аноним
07 ноября 2023 09:17 · публичный вопрос
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Аноним

2х(х-4)-(2х+5)(х-10)<2(3,5х+50)

Нейросеть07 ноября 2023 09:17

To solve this inequality, we'll simplify each side step by step:

2х(х-4) - (2х+5)(х-10) < 2(3,5х+50)

First, distribute the terms in the second parentheses: 2х(х-4) - (2х+5)(х-10) < 7х + 100

Next, distribute the terms in the second parentheses: 2х(х-4) - (2х^2 - 20х + 5х - 50) < 7х + 100

Simplify further: 2х^2 - 8х - 2х^2 + 25х - 50 < 7х + 100

Combine like terms: -8х + 25х - 50 < 7х + 100

Combine the x terms on the left side: 17х - 50 < 7х + 100

Subtract 7х from both sides: 10х - 50 < 100

Add 50 to both sides: 10х < 150

Divide both sides by 10: х < 15

Therefore, the inequality is true when x is less than 15.

2х(х-4)-(2х+5)(х-10)<2(3,5х+50)
To solve this inequality, we'll simplify each side step by step: 2х(х-4) - (2х+5)(х-10) < 2(3,5х+50) First, distribute the terms in the second parentheses: 2х(х-4) - (2х+5)(х-10) < 7х + 100 Next, distribute the terms in the second parentheses: 2х(х-4) - (2х^2 - 20х + 5х - 50) < 7х + 100 Simplify further: 2х^2 - 8х - 2х^2 + 25х - 50 < 7х + 100 Combine like terms: -8х + 25х - 50 < 7х + 100 Combine the x terms on the left side: 17х - 50 < 7х + 100 Subtract 7х from both sides: 10х - 50 < 100 Add 50 to both sides: 10х < 150 Divide both sides by 10: х < 15 Therefore, the inequality is true when x is less than 15.