2y-2/y+3 + y+3/y-3=5

Assuming the equation is (2y - 2)/(y + 3) + (y + 3)/(y - 3) = 5, with y ≠ -3, 3.

Multiply both sides by (y^2 - 9) = (y + 3)(y - 3): (2y - 2)(y - 3) + (y + 3)^2 = 5(y^2 - 9).

Compute: (2y - 2)(y - 3) = 2y^2 - 8y + 6 (y + 3)^2 = y^2 + 6y + 9

Sum: 3y^2 - 2y + 15 = 5y^2 - 45

Bring all to one side: 0 = 2y^2 + 2y - 60 => y^2 + y - 30 = 0

Factor: (y + 6)(y - 5) = 0

Solutions: y = 5 or y = -6 (both satisfy y ≠ ±3).

So the solution set is y = 5 or y = -6.