What you posted is a classic SQL injection payload.
What it does: It tries to terminate the current string in a SQL query, injects a tautology (5*5=25, which is always true), and uses a SQL comment (--) to ignore the rest of the query. This can cause the WHERE clause to always evaluate to true, potentially bypassing authentication.
Why it works: If user input is directly concatenated into a SQL statement, the input can alter the logic of the query rather than just be treated as data.
Defensive takeaways (exam-ready):
- Never build SQL by concatenating user input. Always use parameterized/prepared statements.
- Use a database API that supports placeholders and pass user input as parameters.
- Consider ORM/query builders that automatically parameterize queries.
- Enforce least-privilege database accounts and avoid exposing detailed error messages.
- Validate and sanitize input, but don’t rely on validation alone for security.
Quick examples (conceptual, language-agnostic):
- Vulnerable (unsafe):
- query = "SELECT * FROM users WHERE username = '" + username + "' AND password = '" + password + "'"
- Secure (safe):
- query = "SELECT * FROM users WHERE username = ? AND password = ?"
- bind parameters: (username, password)
- Vulnerable (unsafe):
Short language snippets (illustrative):
- Python (sqlite3/psycopg2 style): cursor.execute("SELECT * FROM users WHERE username = ? AND password = ?", (username, password))
- Java (PreparedStatement): PreparedStatement ps = conn.prepareStatement("SELECT * FROM users WHERE username = ? AND password = ?"); ps.setString(1, username); ps.setString(2, password);
- PHP (PDO): $stmt = $pdo->prepare("SELECT * FROM users WHERE username = :username AND password = :password"); $stmt->execute(['username' => $username, 'password' => $password]);
Important note: Do not test injection on systems you don’t own or have explicit permission to test.
If you want, tell me your language of choice and I’ll tailor a secure example handout for your exam notes.