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Задача Задача №3620068
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Аноним
17 июня 2026 23:03 · публичный вопрос
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Аноним

(select concat(chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||user||chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) from DUAL))

Ответ нейросети
17 июня 2026 23:03

Short explanation:

  • This Oracle SQL snippet is building a string by concatenating ASCII characters. It effectively creates something like: @43701@10734
  • The part comes from the current user (in Oracle you’d typically get this with USER).

What it would produce:

  • If USER returns SCOTT, the result would be: @43701SCOTT@10734

Syntax notes and fixes:

  • The code as written has some syntax issues (CONCAT takes two arguments; you don’t need CONCAT here if you’re using || for concatenation).
  • A clean way using only string concatenation: select chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||USER||chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) from dual;
  • If you prefer to use CONCAT explicitly (two-argument function), you can nest it: select concat(chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||USER, chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52)) from dual;

Notes:

  • chr(64) = @, chr(52)=4, chr(51)=3, chr(55)=7, chr(48)=0, chr(49)=1, chr(49)=1, chr(48)=0, chr(55)=7, chr(51)=3, chr(52)=4. So the literal parts are @43701 and @10734 with the username inserted in between.
  • Be mindful of using user-supplied input in SQL. Obfuscated concatenation like this can be used in injection scenarios; in real applications prefer parameterized queries and clear, maintainable string handling.

If you want, tell me your target Oracle version and I’ll tailor the exact syntax.