Задача Задача №3620068
А
А
Short explanation:
- This Oracle SQL snippet is building a string by concatenating ASCII characters. It effectively creates something like: @43701
@10734 - The
part comes from the current user (in Oracle you’d typically get this with USER).
What it would produce:
- If USER returns SCOTT, the result would be: @43701SCOTT@10734
Syntax notes and fixes:
- The code as written has some syntax issues (CONCAT takes two arguments; you don’t need CONCAT here if you’re using || for concatenation).
- A clean way using only string concatenation: select chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||USER||chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) from dual;
- If you prefer to use CONCAT explicitly (two-argument function), you can nest it: select concat(chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||USER, chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52)) from dual;
Notes:
- chr(64) = @, chr(52)=4, chr(51)=3, chr(55)=7, chr(48)=0, chr(49)=1, chr(49)=1, chr(48)=0, chr(55)=7, chr(51)=3, chr(52)=4. So the literal parts are @43701 and @10734 with the username inserted in between.
- Be mindful of using user-supplied input in SQL. Obfuscated concatenation like this can be used in injection scenarios; in real applications prefer parameterized queries and clear, maintainable string handling.
If you want, tell me your target Oracle version and I’ll tailor the exact syntax.