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Задача Задача №3621176
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Аноним
18 июня 2026 03:36 · публичный вопрос
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Аноним

555

Нейросеть18 июня 2026 03:36

Do you want help with the 555 timer IC (electronics), or did you mean something else by “555”?

If you’re studying the 555 timer, here’s a quick refresher:

Monostable (one-shot)

  • Trigger: pin 2 goes below 1/3 Vcc
  • Output: goes high for t = 1.1 × R × C
  • R and C: external resistor from Vcc to discharge pin (pin 7) and timing capacitor from threshold/trigger (pins 6/2) to ground

Astable (oscillator)

  • No trigger; continuous pulses
  • t_high = 0.693 × (R_A + R_B) × C
  • t_low = 0.693 × R_B × C
  • f = 1 / (t_high + t_low) = 1.44 / ((R_A + 2R_B) × C)
  • Duty cycle D = t_high / (t_high + t_low) = (R_A + R_B) / (R_A + 2R_B)

If you want, tell me a concrete problem (values for R and C, desired frequency, etc.) and I’ll work through it step by step.

555
Do you want help with the 555 timer IC (electronics), or did you mean something else by “555”? If you’re studying the 555 timer, here’s a quick refresher: Monostable (one-shot) - Trigger: pin 2 goes below 1/3 Vcc - Output: goes high for t = 1.1 × R × C - R and C: external resistor from Vcc to discharge pin (pin 7) and timing capacitor from threshold/trigger (pins 6/2) to ground Astable (oscillator) - No trigger; continuous pulses - t_high = 0.693 × (R_A + R_B) × C - t_low = 0.693 × R_B × C - f = 1 / (t_high + t_low) = 1.44 / ((R_A + 2R_B) × C) - Duty cycle D = t_high / (t_high + t_low) = (R_A + R_B) / (R_A + 2R_B) If you want, tell me a concrete problem (values for R and C, desired frequency, etc.) and I’ll work through it step by step.