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Задача Задача №3621428
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Аноним
18 июня 2026 04:04 · публичный вопрос
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Аноним

555

Ответ нейросети
18 июня 2026 04:04

Do you want a quick refresher on the 555 timer, or do you have a specific problem (astable, monostable, or bistable) you want to solve?

If you’d like a concise refresher, here are the essentials:

  • Pinout (common NE/ TLC555, view from top):

    • 1 Ground
    • 2 Trigger
    • 3 Output
    • 4 Reset
    • 5 Control Voltage
    • 6 Threshold
    • 7 Discharge
    • 8 Vcc
  • Modes:

    • Astable (free-running oscillator): generates a square wave, no external trigger needed.
      • f ≈ 1.44 / [(R1 + 2 R2) C]
      • High time Th ≈ 0.693 (R1 + R2) C
      • Low time Tl ≈ 0.693 (R2) C
      • Duty cycle ≈ (R1 + R2) / (R1 + 2 R2)
    • Monostable (one-shot): outputs a pulse when triggered.
      • Pulse width t ≈ 1.1 R C
      • Trigger on pin 2 (negative-going). Reset pin 4 should be high.
    • Bistable (flip-flop): Toggle between states with trigger and reset; no timing capacitor needed.
  • Common equations (typical configurations):

    • R, C units: ohms and farads.
    • For monostable, t = 1.1 R C.
    • For astable, f ≈ 1.44 / [(R1 + 2 R2) C].
    • Control voltage on pin 5 can shift thresholds (usually decoupled with a 0.01 µF cap to ground).
  • Quick example problems:

    • Astable: R1 = 1 kΩ, R2 = 10 kΩ, C = 100 nF
      • f ≈ 1.44 / [(1k + 2×10k) × 100 nF] ≈ 1.44 / (21k × 100e-9) ≈ 685 Hz
      • Duty cycle ≈ (1k + 10k) / (1k + 2×10k) ≈ 11k / 21k ≈ 52%
    • Monostable: R = 10 kΩ, C = 100 nF
      • t ≈ 1.1 × 10k × 100 nF ≈ 1.1 ms

If you tell me your course level or the exact problem type, I can tailor explanations or generate practice problems with solutions.