Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №3621777
А
Аноним
18 июня 2026 04:57 · публичный вопрос
А
Аноним

-1" OR 3*2>999 --

Нейросеть18 июня 2026 04:57

It looks like a SQL injection-style payload: -1" OR 3*2>999 --.

What it does in brief:

  • The 3*2>999 part evaluates to 6>999, which is false.
  • The -- at the end starts a SQL comment, so the rest of the original query is ignored.
  • The string often tries to close a quoted value and inject an OR condition to alter the WHERE clause.

But the actual effect depends on the surrounding query. For example, if the query is something like: SELECT * FROM users WHERE username = "-1" OR 32>999 --; the 32>999 part is false, so the condition reduces to username = "-1" OR FALSE, which is effectively username = "-1" (i.e., no bypass unless -1 is a valid username).

If you’re studying this for defense:

  • This illustrates why you should use parameterized queries (not string concatenation) so injected content can’t break out of quotes.
  • Other defenses: input validation, least-privilege database accounts, proper error handling, and using ORM or prepared statements.

Examples of safe usage (parameterized queries):

  • Python (sqlite3/psycopg2): cursor.execute("SELECT * FROM users WHERE username = ?", (user_input,))
  • Java (PreparedStatement): PreparedStatement ps = conn.prepareStatement("SELECT * FROM users WHERE username = ?"); ps.setString(1, userInput);
  • PHP (PDO): $stmt = $pdo->prepare("SELECT * FROM users WHERE username = :username"); $stmt->execute([':username' => $userInput]);

If you want, tell me the exact exam context (e.g., “analysis of injection strings” or “defensive programming”), and I can tailor explanations or practice questions accordingly.

-1" OR 3*2>999 --
It looks like a SQL injection-style payload: -1" OR 3*2>999 --. What it does in brief: - The 3*2>999 part evaluates to 6>999, which is false. - The -- at the end starts a SQL comment, so the rest of the original query is ignored. - The string often tries to close a quoted value and inject an OR condition to alter the WHERE clause. But the actual effect depends on the surrounding query. For example, if the query is something like: SELECT * FROM users WHERE username = "-1" OR 3*2>999 --; the 3*2>999 part is false, so the condition reduces to username = "-1" OR FALSE, which is effectively username = "-1" (i.e., no bypass unless -1 is a valid username). If you’re studying this for defense: - This illustrates why you should use parameterized queries (not string concatenation) so injected content can’t break out of quotes. - Other defenses: input validation, least-privilege database accounts, proper error handling, and using ORM or prepared statements. Examples of safe usage (parameterized queries): - Python (sqlite3/psycopg2): cursor.execute("SELECT * FROM users WHERE username = ?", (user_input,)) - Java (PreparedStatement): PreparedStatement ps = conn.prepareStatement("SELECT * FROM users WHERE username = ?"); ps.setString(1, userInput); - PHP (PDO): $stmt = $pdo->prepare("SELECT * FROM users WHERE username = :username"); $stmt->execute([':username' => $userInput]); If you want, tell me the exact exam context (e.g., “analysis of injection strings” or “defensive programming”), and I can tailor explanations or practice questions accordingly.