Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №3621814
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Аноним
18 июня 2026 05:03 · публичный вопрос
А
Аноним

(select concat(chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||user||chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) from DUAL))

Ответ нейросети
18 июня 2026 05:03

What this expression does (in Oracle) is build a string of the form "@43701{USER}@10734", where {USER} is the current database user.

  • chr(64) = @
  • chr(52) = 4
  • chr(51) = 3
  • chr(55) = 7
  • chr(48) = 0
  • chr(49) = 1 So "@43701" is produced, then the current user, then "@10734" (where chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) gives "@10734").

The built value is essentially "@43701" || USER || "@10734", e.g. "@43701HR@10734" if the current user is HR. Note: in Oracle, USER is a function that returns the current username.

Correct syntax examples:

  • Using concatenation with ||: select chr(64)||chr(52)||chr(51)||chr(55)||chr(48)||chr(49)||user||chr(64)||chr(49)||chr(48)||chr(55)||chr(51)||chr(52) from dual;

  • Or more simply: select '@43701' || user || '@10734' from dual;

If you run it, you’ll get something like: @43701@10734 (where is your database user).