Задача Задача №3622653
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Here are quick notes and a small practice set around the number 555 for exam prep.
Key facts
- Decimal factorization: 555 = 3 × 5 × 37
- Divisible by: 3, 5, 15 (and thus by 1, 3, 5, 15, 37, 111, 185, 555)
- Not divisible by: 9, 7, 11
- Roman numeral: DLV
- Binary: 1000101011
- Hexadecimal: 0x22B
Practice questions
- Is 555 divisible by 9? Explain briefly.
- Find gcd(555, 270).
- Compute lcm(555, 14).
- Convert 555 to Roman numerals (confirm your answer).
- Write 555 in binary (show the steps).
Suggested answers
- No. Sum of digits is 15, which is not a multiple of 9.
- gcd(555, 270) = 15.
- gcd(555, 14) = 1, so lcm = 555 × 14 = 7770.
- 555 = 3 × 5 × 37, so Roman numeral is DLV.
- Binary: 1000101011.
Would you like more problems on divisibility, factorization, or another subject area?
