Answer: \(x=2\) or \(x=3\).
Solution
Factor the quadratic:
\[ x^2-5x+6=0 \]
Find two numbers whose:
- product is \(6\);
- sum is \(-5\).
These numbers are \(-2\) and \(-3\). Therefore,
\[ x^2-5x+6=(x-2)(x-3). \]
So,
\[ (x-2)(x-3)=0. \]
A product equals zero if at least one factor equals zero:
\[ x-2=0 \quad \text{or} \quad x-3=0. \]
Hence,
\[ \boxed{x=2 \text{ or } x=3}. \]
Check
\[ 2^2-5\cdot2+6=4-10+6=0, \]
\[ 3^2-5\cdot3+6=9-15+6=0. \]
Both solutions are correct.
