Задача Задача №3625535
А
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Answer: \(x=2\) or \(x=3\).
Solution
Factor the quadratic:
\[ x^2-5x+6=0 \]
Find two numbers whose product is \(6\) and whose sum is \(-5\). They are \(-2\) and \(-3\):
\[ (x-2)(x-3)=0 \]
By the zero-product rule:
\[ x-2=0 \quad \text{or} \quad x-3=0 \]
Therefore,
\[ \boxed{x=2 \text{ or } x=3} \]
Check
\[ 2^2-5\cdot2+6=4-10+6=0 \]
\[ 3^2-5\cdot3+6=9-15+6=0 \]
Both solutions are correct.
