Evaluating speed values
I’m calculating a time difference of 2 minutes and 20 seconds, with potential speeds of 5.4 km/h and 7.2 km/h leading to exact time values. It seems these numbers were chosen carefully! If I consider a speed of 17.2 km/h instead, I'd end up with a complex number that doesn't fit nicely. Maybe I misread the value; the line in the image seems to indicate 7.2 instead of 17.2. I should double-check that visual detail.Analyzing displayed values
I'm examining a line that shows v = 17,2 км/с, but I suspect that the mark before the comma looks more like a "7" than a "1." Initially, I misread it as 17.2 because of a stroke. The more accurate reading seems to be v = 7,2 км/с. I also need to confirm the units, likely м/с. Looking at another line, v = 5,4 км/с, suggests it could mean 5.4 m/s, and if distances are 840 m, the time calculations seem off. I need to mentally rotate the image for better clarity.Clarifying unit interpretation
I'm trying to figure out the unit after 5.4. I see "км/с," and I think the first letter after the slash looks like it might be с. This leads me to believe that I should interpret this as kilometers per second. It’s important that I confirm the correct unit because it could affect my calculations. I need to ensure I have the right understanding before moving forward with any numbers or formulas!Calculating time differences
Let's put together a quick answer: the time difference is 140 seconds, or 2 minutes and 20 seconds, using speeds of 5.4 km/h and 7.2 km/h. First, I need to convert those speeds into meters per second. The calculations show that the faster speed gives a shorter time, which makes sense! I notice the details in the photo about the units could be important, especially if there's any confusion about numbers, like if it might read differently. Let's double-check that!
Краткий ответ:
\[
\boxed{\Delta t=140\ \text{с}=2\ \text{мин }20\ \text{с}}
\]
Переведём скорости в СИ:
\[ v_1=5{,}4\ \frac{\text{км}}{\text{ч}}=1{,}5\ \frac{\text{м}}{\text{с}}, \qquad v_2=7{,}2\ \frac{\text{км}}{\text{ч}}=2\ \frac{\text{м}}{\text{с}}. \]
Время движения на расстояние \(L=840\) м:
\[ t_1=\frac{L}{v_1}=\frac{840}{1{,}5}=560\ \text{с}, \]
\[ t_2=\frac{L}{v_2}=\frac{840}{2}=420\ \text{с}. \]
Разность времени:
\[ \Delta t=t_1-t_2=560-420=140\ \text{с}. \]
Более быстрый участник затратил на путь на \(140\) с меньше.