34. Иә: \[ \overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC},\qquad \overrightarrow{BD}=\overrightarrow{BC}+\overrightarrow{CD}. \] \(\overrightarrow{AB}=\overrightarrow{CD}\) болғандықтан, \[ \boxed{\overrightarrow{AC}=\overrightarrow{BD}}. \]
35. \[ AB=\sqrt{AC^2+BC^2}=\sqrt{12^2+5^2}=13\text{ см}. \] \[ CM=\frac{AB}{2}=6{,}5\text{ см},\qquad MN=\frac{BC}{2}=2{,}5\text{ см}. \]
Жауабы: \(\boxed{AB=13\text{ см},\ CM=6{,}5\text{ см},\ MN=2{,}5\text{ см}}\).
36. \[ \frac{AD}{CD}=\frac{AB}{BC}=\frac{6}{10}=\frac35,\qquad AD+CD=12. \] \[ \boxed{AD=4{,}5\text{ см},\quad CD=7{,}5\text{ см}}. \]