Задача Задача №3644823
А
А
\(\dfrac{4^7}{2^7}:2^3=2^7:2^3=2^4=16\).
\[ \frac{80^4-7^4}{73\cdot87} =\frac{(80-7)(80+7)(80^2+7^2)}{73\cdot87} =80^2+7^2=6449. \]
\(\dfrac{4^7}{2^7}:2^3=2^7:2^3=2^4=16\).
\[ \frac{80^4-7^4}{73\cdot87} =\frac{(80-7)(80+7)(80^2+7^2)}{73\cdot87} =80^2+7^2=6449. \]