Задача Задача №3647747
А
А
\[ \frac{\frac{5}{12}+\frac{1}{3}}{72} =\frac{\frac{9}{12}}{72} =\frac{3}{4\cdot72} =\boxed{\frac{1}{96}}. \]
\[ \frac{\frac{5}{12}+\frac13}{72} =\frac{\frac34}{72} =\frac{1}{96}. \]
\[ \boxed{\frac{1}{96}} \]
\[ \frac{\frac{5}{12}+\frac{1}{3}}{72} =\frac{\frac{9}{12}}{72} =\frac{3}{4\cdot72} =\boxed{\frac{1}{96}}. \]
\[ \frac{\frac{5}{12}+\frac13}{72} =\frac{\frac34}{72} =\frac{1}{96}. \]
\[ \boxed{\frac{1}{96}} \]