Задача Задача №3651074
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Answer: \(x=2\) or \(x=3\).
Factor the quadratic: \[ x^2-5x+6=(x-2)(x-3) \]
Now use the zero-product rule: if \[ (x-2)(x-3)=0, \] then one of the factors must equal zero:
\[ x-2=0 \Rightarrow x=2, \] \[ x-3=0 \Rightarrow x=3. \]
Check:
- \(2^2-5\cdot2+6=4-10+6=0\)
- \(3^2-5\cdot3+6=9-15+6=0\)
So the solutions are \(\boxed{x=2,\;3}\).