Алгебра · 7 класс Задача №3654566
А
А
\(7{,}7\cdot5{,}3=40{,}81\)
\(\frac78:\frac56=\frac78\cdot\frac65=\frac{21}{20}=1\frac1{20}\)
\(\frac1{25}-\frac7{50}=\frac2{50}-\frac7{50}=-\frac1{10}\)
\(4{,}7-8{,}2=-3{,}5\)
\(12\frac25\cdot5=62\)
\(\frac15-\frac{41}{50}=\frac{10}{50}-\frac{41}{50}=-\frac{31}{50}\)
\(6{,}9+7{,}4=14{,}3\)
\(9{,}6:1{,}6=6\)
\(3{,}9-7{,}3=-3{,}4\)
\(\frac{21}{5}\cdot\frac37=\frac95=1\frac45\)