Solving proportions
I need to solve the problem №131 involving the four simple proportions in the first row. Let’s analyze it carefully. The first part is "176 : (2x) = 15 : 25," and I'm confirming that it’s indeed "176." I'll calculate it like this: 176/(2x) = 15/25 simplifies to 3/5. This leads to 176 times 5 equals 15 times 2x, which gives me the equation 880 = 30x. Thus, x equals 88/3, which is approximately 29.333.Calculating equations and ratios
I'm working through some math calculations and it gets a bit tangled! I started with 30x equating to 440/3, realizing that I made mistakes in simplifying. I go through cross multiplication and solving for x in various equations, recovering back to the ratio of 88/x and correcting my approach by ensuring the math aligns properly. I eventually simplify my findings down affirmatively and arrive at ratios, all while keeping track of my steps carefully. It's a little overwhelming, but I think I’m getting there!Calculating proportions
Okay, I’m calculating proportions here. I made a mistake before, thinking x could be 2 instead of 2.5. I’ve confirmed it as x=5/2! I need to look at the image to inspect the number, which appears to be "176". I'm thinking it wouldn't include a comma, so I'll stick with 176 as an integer. It looks like this is related to some school exercise. I should provide a brief answer in Russian, then outline the necessary verification steps.Explaining proportions with fractions
I need to follow the developer's instructions carefully. After giving the main answer, I’ll include a meaningful next step related to solving proportions with fractions. The ratio property says in a:b = c:d, then ad = bc, but I must emphasize x ≠ 0. For task 131, I should confirm it involves just four items.
I’ve derived x from the proportion 176:(2x) = 15:25. After cross-multiplying, I find x = 440/3. Verification checks out; the left-hand side equals 15/25.
[[NEXT]] Покажи, как решать пропорции с дробями.Analyzing textbook exercises
I'm considering whether the answer manual is acceptable, but I want to explore the textbook structure more. The page shows headings in both Kazakh and Russian, with instructions to "solve equations." The exercises may come from A.G. Мерзляк for grade 6 math, with a focus on solving for x. I’m also wondering about the use of decimals and how numbers may have been printed, especially regarding visibility of the decimal point. I might want to concentrate on exercise number 131, skipping the others for now.
Краткий ответ:
- \(x=\dfrac{440}{3}=146\dfrac{2}{3}\);
- \(x=3\);
- \(x=\dfrac{16}{65}\);
- \(x=2{,}5\).
Правило
В пропорции
\[
a:b=c:d
\]
произведение крайних членов равно произведению средних:
\[
a\cdot d=b\cdot c.
\]
Решение
1)
\[
176:(2x)=15:25
\]
\[
176\cdot25=15\cdot2x
\]
\[
4400=30x,\qquad x=\frac{4400}{30}=\frac{440}{3}.
\]
Проверка: \[ \frac{176}{2\cdot\frac{440}{3}}=\frac35=\frac{15}{25}. \]
2)
\[
44:99=4:(3x)
\]
\[
44\cdot3x=99\cdot4
\]
\[
132x=396,\qquad x=3.
\]
3)
\[
(5x):8=8:52
\]
\[
5x\cdot52=8\cdot8
\]
\[
260x=64,\qquad x=\frac{64}{260}=\frac{16}{65}.
\]
4)
\[
10{,}5:21=(4x):20
\]
\[
10{,}5\cdot20=21\cdot4x
\]
\[
210=84x,\qquad x=\frac{210}{84}=2{,}5.
\]
Проверка последнего равенства: \[ \frac{10{,}5}{21}=\frac12,\qquad \frac{4\cdot2{,}5}{20}=\frac{10}{20}=\frac12. \]