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Пришли, пожалуйста, изображение ещё раз: сейчас условие варианта 2.1.2 не отображается.

Вариант 2.1.2

1. \(\dfrac14+\dfrac13=\dfrac3{12}+\dfrac4{12}=\boxed{\dfrac7{12}}\)

2. \(\dfrac25+\dfrac1{10}=\dfrac4{10}+\dfrac1{10}=\boxed{\dfrac12}\)

3. \(\dfrac18+\dfrac16=\dfrac3{24}+\dfrac4{24}=\boxed{\dfrac7{24}}\)

4. \(11+\dfrac7{15}=\boxed{11\dfrac7{15}}\)

5. \(6+2\dfrac{17}{40}=\boxed{8\dfrac{17}{40}}\)

6. \(3\dfrac8{21}+\dfrac{13}{21}=3+\dfrac{21}{21}=\boxed4\)

7. \(\dfrac34+\dfrac7{12}=\dfrac9{12}+\dfrac7{12}=\dfrac{16}{12}=\boxed{1\dfrac13}\)

8. \(\dfrac7{10}+8\dfrac35=\dfrac7{10}+8\dfrac6{10}=\boxed{9\dfrac3{10}}\)

Вариант 2.1.2

1. \[ \frac14+\frac13=\frac3{12}+\frac4{12}=\frac7{12} \]

2. \[ \frac25+\frac1{10}=\frac4{10}+\frac1{10}=\frac5{10}=\frac12 \]

3. \[ \frac18+\frac16=\frac3{24}+\frac4{24}=\frac7{24} \]

4. \[ 11+\frac7{15}=11\frac7{15} \]

5. \[ 6+2\frac{17}{40}=8\frac{17}{40} \]

6. \[ 3\frac8{21}+\frac{13}{21} =3+\frac{21}{21}=4 \]

7. \[ \frac34+\frac7{12}=\frac9{12}+\frac7{12} =\frac{16}{12}=1\frac13 \]

8. \[ \frac7{10}+8\frac35 =\frac7{10}+8\frac6{10} =8\frac{13}{10}=9\frac3{10} \]

Ответы:
\[ \boxed{\frac7{12};\ \frac12;\ \frac7{24};\ 11\frac7{15};\ 8\frac{17}{40};\ 4;\ 1\frac13;\ 9\frac3{10}} \]

Вариант 2.1.2

1. \[ \frac14+\frac13=\frac3{12}+\frac4{12}=\frac7{12} \]

2. \[ \frac25+\frac1{10}=\frac4{10}+\frac1{10}=\frac5{10}=\frac12 \]

3. \[ \frac18+\frac16=\frac3{24}+\frac4{24}=\frac7{24} \]

4. \[ 11+\frac7{15}=11\frac7{15} \]

5. \[ 6+2\frac{17}{40}=8\frac{17}{40} \]

6. \[ 3\frac8{21}+\frac{13}{21} =3\frac{21}{21}=4 \]

7. \[ \frac34+\frac7{12} =\frac9{12}+\frac7{12} =\frac{16}{12}=1\frac13 \]

8. \[ \frac7{10}+8\frac35 =8+\frac7{10}+\frac6{10} =8\frac{13}{10}=9\frac3{10} \]

Ответы:
\[ \boxed{\frac7{12};\ \frac12;\ \frac7{24};\ 11\frac7{15};\ 8\frac{17}{40};\ 4;\ 1\frac13;\ 9\frac3{10}} \]