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Алгебра · 7 класс Задача №3659739
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Аноним
16 сентября 2026 06:47 · публичный вопрос
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Аноним

1.13 1.14 1.15ті шығар

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Қысқаша жауап

1.13

  1. \(\displaystyle \frac{24181}{24}=1007\frac{13}{24}\)

  2. \(\displaystyle -\frac{2915}{27}=-107\frac{26}{27}\)

  3. \(\displaystyle \frac{103079}{144}=715\frac{119}{144}\)

  4. \(\displaystyle -\frac{16}{15}\)

1.14

  1. \(\displaystyle x=\frac1{27}\)

  2. \(\displaystyle x=2916\)

  3. \(\displaystyle x=\frac{625}{24}=26\frac1{24}\)

  4. \(\displaystyle x=\frac{81}{16}=5\frac1{16}\)

1.15

  1. \(\displaystyle 8^3-600<7^2-44\)

  2. \(\displaystyle -10^4+9^4<(-1)^5\)

  3. \(\displaystyle 0{,}4^3+1{,}6\cdot1{,}1>1{,}5^3-11\cdot0{,}58\)

  4. \(\displaystyle (-2{,}2)^3+0{,}603\cdot24>368-2^3\cdot6^4\)

Амалдардың реті: дәрежелеу → көбейту/бөлу → қосу/азайту.

1.13. Амалдарды орындау

  1. \[ 10^3-5^2:8+\left(\frac23\right)^5\cdot81 \] \[ =1000-\frac{25}{8}+\frac{32}{243}\cdot81 =1000-\frac{25}{8}+\frac{32}{3} \] \[ =\frac{24000-75+256}{24} =\frac{24181}{24}. \]

  2. \[ 243\cdot\left(\frac13\right)^8+6^2(25-28) \] \[ =3^5\cdot\frac1{3^8}+36(-3) =\frac1{27}-108 =-\frac{2915}{27}. \]

  3. \[ 9^3-15^2:16+\frac34:\frac{27}{32} \] \[ =729-\frac{225}{16}+\frac34\cdot\frac{32}{27} =729-\frac{225}{16}+\frac89 \] \[ =\frac{103079}{144}. \]

  4. \[ (7^2-51)\cdot\frac59+3{,}6:9^2 \] \[ =(49-51)\cdot\frac59+\frac{3{,}6}{81} =-2\cdot\frac59+\frac{2}{45} \] \[ =-\frac{10}{9}+\frac{2}{45} =-\frac{50}{45}+\frac{2}{45} =-\frac{16}{15}. \]

1.14. \(x\)-ті табу

  1. \[ x=\left(\frac12\right)^4\cdot48:3^4 =\frac1{16}\cdot\frac{48}{81} =\frac1{27}. \]

  2. \[ x=3^8\cdot2^4\cdot\left(\frac16\right)^2 =3^8\cdot2^4\cdot\frac1{2^2\cdot3^2} \] \[ =3^6\cdot2^2=729\cdot4=2916. \]

  3. \[ x=\left(\frac56\right)^2\cdot24:\left(\frac45\right)^2 \] \[ =\frac{25}{36}\cdot24\cdot\frac{25}{16} =\frac{625}{24}. \]

  4. \[ x=\left(\frac23\right)^2\cdot27\cdot\left(\frac34\right)^3 \] \[ =\frac49\cdot27\cdot\frac{27}{64} =12\cdot\frac{27}{64} =\frac{81}{16}. \]

1.15. Мәндерін салыстыру

  1. \[ 8^3-600=512-600=-88,\qquad 7^2-44=49-44=5. \] Сондықтан: \[ -88<5. \]

  2. \[ -10^4+9^4=-10000+6561=-3439, \qquad (-1)^5=-1. \] Сондықтан: \[ -3439<-1. \]

  3. \[ 0{,}4^3+1{,}6\cdot1{,}1 =0{,}064+1{,}76=1{,}824, \] \[ 1{,}5^3-11\cdot0{,}58 =3{,}375-6{,}38=-3{,}005. \] Сондықтан: \[ 1{,}824>-3{,}005. \]

  4. \[ (-2{,}2)^3+0{,}603\cdot24 =-10{,}648+14{,}472=3{,}824, \] \[ 368-2^3\cdot6^4 =368-8\cdot1296 =368-10368=-10000. \] Сондықтан: \[ 3{,}824>-10000. \]