Задача Задача №3660159
А
А
Answer: \(\boxed{x=2 \text{ or } x=3}\)
Factor the quadratic: \[ x^2-5x+6=(x-2)(x-3) \]
So: \[ (x-2)(x-3)=0 \]
A product is zero if at least one factor is zero: \[ x-2=0 \Rightarrow x=2 \] \[ x-3=0 \Rightarrow x=3 \]
Check:
- \(2^2-5\cdot2+6=4-10+6=0\)
- \(3^2-5\cdot3+6=9-15+6=0\)
