Краткие ответы:
- \(1\)
- \(\dfrac{7}{25}\)
- \(6\)
- \(5\)
- \(72\)
- \(1\)
- \(125\)
Решение
2)
\[
\frac{(4\sqrt5)^2}{80}
=\frac{4^2\cdot(\sqrt5)^2}{80}
=\frac{16\cdot5}{80}
=\frac{80}{80}=1.
\]
4)
\[
\frac{147}{(5\sqrt{21})^2}
=\frac{147}{25\cdot21}
=\frac{7\cdot21}{25\cdot21}
=\frac{7}{25}.
\]
6)
\[
\frac{\sqrt{432}}{2\sqrt3}
=\frac{\sqrt{144\cdot3}}{2\sqrt3}
=\frac{12\sqrt3}{2\sqrt3}=6.
\]
8)
\[
\frac{\sqrt{175}}{\sqrt7}
=\frac{\sqrt{25\cdot7}}{\sqrt7}
=\frac{5\sqrt7}{\sqrt7}=5.
\]
10)
\[
\sqrt{18\cdot12}\cdot\sqrt{24}
=\sqrt{18\cdot12\cdot24}
=\sqrt{5184}=72.
\]
12)
\[
\sqrt3\cdot\sqrt{12}-5
=\sqrt{36}-5
=6-5=1.
\]
14)
\[
\sqrt{5^6}=5^3=125,
\]
так как \(\sqrt{a^{2n}}=a^n\) при \(a>0\).
Главные правила: \[ \sqrt a\cdot\sqrt b=\sqrt{ab},\qquad (\sqrt a)^2=a,\qquad (a\sqrt b)^2=a^2b. \]
