\(\frac{10}{50}+\frac{53}{50}=\frac{63}{50}=1\frac{13}{50}\)
\(\frac{2}{20}+\frac{29}{20}=\frac{31}{20}=1\frac{11}{20}\)
\(\frac{5}{10}+\frac{11}{10}=\frac{16}{10}=\frac85=1\frac35\)
\(\frac{5}{20}+\frac{37}{20}=\frac{42}{20}=\frac{21}{10}=2\frac1{10}\)
\(\frac{10}{20}+\frac{31}{20}=\frac{41}{20}=2\frac1{20}\)
\(\frac{25}{50}+\frac{33}{50}=\frac{58}{50}=\frac{29}{25}=1\frac4{25}\)
\(\frac{2}{10}+\frac{17}{10}=\frac{19}{10}=1\frac9{10}\)
\(\frac{2}{50}+\frac{43}{50}=\frac{45}{50}=\frac9{10}\)
\(\frac{5}{50}+\frac{21}{50}=\frac{26}{50}=\frac{13}{25}\)
\(\frac{10}{50}+\frac{19}{50}=\frac{29}{50}\)
\(\frac{10}{50}-\frac{41}{50}=-\frac{31}{50}\)
\(\frac{5}{20}-\frac{51}{20}=-\frac{46}{20}=-\frac{23}{10}\)
\(\frac{5}{10}-\frac{9}{10}=-\frac4{10}=-\frac25\)
\(\frac{10}{20}-\frac{49}{20}=-\frac{39}{20}\)
Задача · 9 класс Задача №3665346
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