Сделай с решением

1. \(\dfrac{-(x+y)}{x+y}=-1\)

2. \(\dfrac{-2(a+b)}{a+b}=-2\)

3. \(\dfrac{x+3}{-5(x+3)}=-\dfrac15\)

4. \(\dfrac{2(b+1)}{-(b+1)}=-2\)

5. \(\dfrac{-(x-3)}{12(x-3)}=-\dfrac1{12}\)

6. \(\dfrac{(a+5)^2}{(a+5)(5-a)}=\dfrac{a+5}{5-a}\)

7. \(\dfrac{13+x}{(x+13)b}=\dfrac1b\)

8. \(\dfrac{-(y-1)}{-(1+y)}=\dfrac{y-1}{y+1}\)

9. \(\dfrac{2(a-b)}{3(b-a)}=-\dfrac23\)

10. \(\dfrac{5(x-y)}{a(y-x)}=-\dfrac5a\)

11. \(\dfrac{x(y+3)}{2(-y-3)}=-\dfrac x2\)

12. \(\dfrac{5(a-2)}{3(a-2)}=\dfrac53\)

13. \(\dfrac{y-1}{3(y-1)}=\dfrac13\)

14. \(\dfrac{a(a-1)}{-(1-a)}=a\)

15. \(\dfrac{(y-1)^2}{(1-y)(1+y)}=-\dfrac{y-1}{y+1}\)

16. \(\dfrac{(y+1)(y-1)}{-(y-1)}=-(y+1)\)

17. \(\dfrac{-2(a-b)}{(a-b)^2}=-\dfrac2{a-b}\)

18. \(\dfrac{x-3}{(3-x)^2}=\dfrac1{x-3}\)

19. \(\dfrac{(b-1)^2}{(1-b)(1+b)}=-\dfrac{b-1}{b+1}\)

20. \(\dfrac{(a+3)(a-3)}{(3-a)^2}=\dfrac{a+3}{a-3}\)

21. \(\dfrac{(y-2)(y+2)}{(2+y)^2}=\dfrac{y-2}{y+2}\)

22. \(\dfrac{-(a-2)}{(2-a)(a+2)}=\dfrac1{a+2}\)

23. \(\dfrac{(x-1)(x+1)}{(1-x)(-x-1)}=1\)

24. \(\dfrac{-(x-1)(1-x)}{(x-1)^2}=1\)

Все сокращения выполнены при допустимых значениях переменных.