Математика · 6 класс Задача №3673075
А
А
\[ \frac{35}{48}:\left(\frac{11}{16}+\frac{3}{32}\right)-\frac{14}{15}\cdot\frac57 =\frac{35}{48}:\frac{25}{32}-\frac23 =\frac{14}{15}-\frac{10}{15} =\boxed{\frac4{15}} \]
\[ \frac{35}{48}:\left(\frac{11}{16}+\frac{3}{32}\right)-\frac{14}{15}\cdot\frac57 =\frac{35}{48}:\frac{25}{32}-\frac23 =\frac{14}{15}-\frac{10}{15} =\boxed{\frac4{15}} \]
