Реши задание на изображении

1.

а) \(\dfrac{(3c+a)-(a-7c)}{4c}=\dfrac52,\quad c\ne0.\)

б) \(\dfrac{2p+3-p}{p+3}=1,\quad p\ne-3.\)

в) \(\dfrac{x^2-4x}{x-4}=x,\quad x\ne4.\)

г) \(\dfrac{m-n}{(m-n)(m+n)}=\dfrac1{m+n},\quad m\ne\pm n.\)

2.

а) \(\dfrac{y(y-3)+3y}{y-3}=\dfrac{y^2}{y-3},\quad y\ne3.\)

б) \(\dfrac{10x+(x+5)(x-5)}{5x(x-5)} =\dfrac{x^2+10x-25}{5x(x-5)},\quad x\ne0,5.\)

в) \(\dfrac{4(x-4)-x(x+4)}{x^2-16} =-\dfrac{x^2+16}{x^2-16},\quad x\ne\pm4.\)

г) \[ \dfrac{q(2p-q)+p(p-2q)}{pq(p+q)} =\dfrac{p-q}{pq},\quad p\ne0,\ q\ne0,\ p+q\ne0. \]

3.

а) \[ \dfrac{(x+5)^2}{x(x+5)(5-x)} =\dfrac{x+5}{x(5-x)},\quad x\ne-5,0,5. \]

б) \[ \dfrac{x^2-3x+9+9x}{(x+3)(x^2-3x+9)} =\dfrac{x+3}{x^2-3x+9},\quad x\ne-3. \]

в) \[ \dfrac{2(x-6)+12-x(1-x)}{x(x-6)} =\dfrac{x+1}{x-6},\quad x\ne0,6. \]