Задача Задача №3699192
А
А
Здание 4,5
4. \(\mathrm{C_{12}H_{22}O_{11}}\)
\[ M_r=12\cdot12+22\cdot1+11\cdot16=342 \]
\[ w(\mathrm C)=\frac{144}{342}\cdot100\%\approx42{,}1\% \] \[ w(\mathrm H)=\frac{22}{342}\cdot100\%\approx6{,}4\% \] \[ w(\mathrm O)=\frac{176}{342}\cdot100\%\approx51{,}5\% \]
Ответ: \(M_r=342\); \(w(\mathrm C)=42{,}1\%\), \(w(\mathrm H)=6{,}4\%\), \(w(\mathrm O)=51{,}5\%\).
5.
\[ \begin{aligned} M_r(\mathrm{H_2S})&=2+32=34;\\ M_r(\mathrm{SO_3})&=32+48=80;\\ M_r(\mathrm{Na_2CO_3})&=46+12+48=106;\\ M_r(\mathrm{Cu(OH)_2})&=64+2(16+1)=98;\\ M_r(\mathrm{P_2O_5})&=62+80=142;\\ M_r(\mathrm{AlCl_3})&=27+3\cdot35{,}5=133{,}5;\\ M_r(\mathrm{Ba(NO_3)_2})&=137+2(14+48)=261. \end{aligned} \]
