Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача · 8 класс Задача №3706062
А
Аноним
02 октября 2026 02:21 · публичный вопрос
А
Аноним

Answer by using the graph

Ответ нейросети

Краткий ответ:

  1. Перенесите данный график в работу.
  2. As volume increases, pressure decreases.
  3. Yes, the trendline is a reasonable representation for this small range of data.
  4. \(c \approx 5500\ \text{pressure-units}\cdot\text{mL}\).
  5. At \(V=100\text{ mL}\), the pressure would be approximately 55 pressure units.

Объяснение:

The equation is

\[ P=\frac{c}{V}. \]

Therefore,

\[ c=P\cdot V. \]

Using the approximate point \(V=50\text{ mL}\), \(P=110\):

\[ c=110\cdot50=5500. \]

For \(V=100\text{ mL}\):

\[ P=\frac{5500}{100}=55. \]

Проверка: при увеличении объёма давление уменьшается, что соответствует графику и закону Бойля.

Обсуждение

4 сообщения
А
Аноним

Write it in English

Нейросеть

Short answer

  1. Copy the graph into your work.
  2. As the volume increases, the pressure decreases.
  3. Yes, the trendline is a reasonable representation of the data.
  4. \(c \approx 5500\ \text{pressure units}\cdot\text{mL}\).
  5. When \(V=100\text{ mL}\), the pressure is approximately 55 pressure units.

Explanation

The equation is

\[ P=\frac{c}{V}. \]

Therefore,

\[ c=P\cdot V. \]

Using the approximate point \(V=50\text{ mL}\) and \(P=110\):

\[ c=110\cdot50=5500. \]

For \(V=100\text{ mL}\):

\[ P=\frac{5500}{100}=55. \]

This agrees with the graph: as volume increases, pressure decreases.

А
Аноним

Can you make 5 like it’s wrote on a computer

Нейросеть
  1. If V = 100 mL, then P = 5500 ÷ 100 = 55 pressure units. Therefore, the pressure would be approximately 55 pressure units.