Математика · 8 класс Задача №3726555
А
А
а) \[ \frac{(a-1)(a+1)}{a-b}\cdot\frac{7(a-b)}{a(a+1)} =\frac{7(a-1)}{a}. \]
б) \[ \frac{b(b+2c)}{b+3}\cdot\frac{5(b+3)}{(b-2c)(b+2c)} =\frac{5b}{b-2c}. \]
а) \[ \frac{(a-1)(a+1)}{a-b}\cdot\frac{7(a-b)}{a(a+1)} =\frac{7(a-1)}{a}. \]
б) \[ \frac{b(b+2c)}{b+3}\cdot\frac{5(b+3)}{(b-2c)(b+2c)} =\frac{5b}{b-2c}. \]