Реши до 6

\(7\sqrt3-\sqrt3=6\sqrt3\) — в)

\(\sqrt{18}=3\sqrt2\) — в)

\(\dfrac{3}{\sqrt6}=\dfrac{\sqrt6}{2}\).

\[ -\!2\sqrt5+\sqrt5=-\sqrt5,\quad -\!2\sqrt5-\sqrt5=-3\sqrt5, \] \[ (-2\sqrt5)\cdot\sqrt5=-10,\quad \dfrac{-2\sqrt5}{\sqrt5}=-2. \]

\[ \sqrt{125}+3\sqrt5-\sqrt{80}=5\sqrt5+3\sqrt5-4\sqrt5=4\sqrt5. \]

\[ (3\sqrt3+\sqrt{13})(\sqrt{13}-3\sqrt3)=13-27=-14. \]