Задача Задача №3734244
А
А
\[ \frac{x^2-y^2}{xy}:\frac{x-y}{3y}\cdot\frac1{x+y} =\frac{(x-y)(x+y)}{xy}\cdot\frac{3y}{x-y}\cdot\frac1{x+y} =\boxed{\frac3x}. \]
\(x\ne0,\ y\ne0,\ x\ne\pm y\).
\[ \frac{x^2-y^2}{xy}:\frac{x-y}{3y}\cdot\frac1{x+y} =\frac{(x-y)(x+y)}{xy}\cdot\frac{3y}{x-y}\cdot\frac1{x+y} =\boxed{\frac3x}. \]
\(x\ne0,\ y\ne0,\ x\ne\pm y\).
