Задача Задача №3736543
А
А
Answer: \(\boxed{x=2 \text{ or } x=3}\)
Factor the quadratic:
\[ x^2-5x+6=(x-2)(x-3) \]
Set each factor equal to zero:
\[ x-2=0 \Rightarrow x=2 \]
\[ x-3=0 \Rightarrow x=3 \]
Check:
- For \(x=2\): \(2^2-5\cdot2+6=4-10+6=0\)
- For \(x=3\): \(3^2-5\cdot3+6=9-15+6=0\)
So both values are correct.