160 упр

160.

а) \(\left(3\frac7{30}-1\frac5{12}\right):18\frac16=\frac{109}{60}:\frac{109}{6}=\frac1{10}\);

б) \(\left(1\frac12+2\frac23\right):1\frac23=\frac{25}{6}:\frac53=\frac52=2\frac12\);

в) \(\left(\frac{11}{18}-1\frac7{12}\right)\left(2\frac16+\frac7{30}\right)=-\frac{35}{36}\cdot\frac{12}{5}=-\frac73\);

г) \(\left(3\frac25-5\right)\left(\frac{31}{48}+\frac7{24}\right)=-\frac85\cdot\frac{15}{16}=-\frac32\).