Задача Задача №3745086
А
А
\[ \frac49+\frac5{12}-\frac34=\frac{16+15-27}{36}=\frac19 \]
\[ \frac9{14}+\frac8{21}-\frac23=\frac{27+16-28}{42}=\frac5{14} \]
\[ \frac56+\frac34-\frac12=\frac{10+9-6}{12}=\frac{13}{12}=1\frac1{12} \]
\[ \frac49+\frac5{12}-\frac34=\frac{16+15-27}{36}=\frac19 \]
\[ \frac9{14}+\frac8{21}-\frac23=\frac{27+16-28}{42}=\frac5{14} \]
\[ \frac56+\frac34-\frac12=\frac{10+9-6}{12}=\frac{13}{12}=1\frac1{12} \]