Реши примеры под номер 977

\[ \begin{aligned} \text{а)}&\ 6\cdot12^{-1}=\frac{6}{12}=\frac12=0{,}5\\ \text{б)}&\ -4\cdot8^{-2}=-\frac{4}{64}=-\frac1{16}\\ \text{в)}&\ 6^{-1}-3^{-2}=\frac16-\frac19=\frac1{18}\\ \text{г)}&\ 1{,}3^0-1{,}3^{-1}=1-\frac{10}{13}=\frac3{13}\\ \text{д)}&\ 12-\left(\frac16\right)^{-1}=12-6=6\\ \text{е)}&\ 25+0{,}1^{-2}=25+100=125 \end{aligned} \]