Массовые доли элементов:
NaNO₃, \(M=85\):
\(\omega(\text{Na})=\frac{23}{85}=27{,}1\%\)
\(\omega(\text{N})=\frac{14}{85}=16{,}5\%\)
\(\omega(\text{O})=\frac{48}{85}=56{,}5\%\)H₃PO₄, \(M=98\):
\(\omega(\text{H})=\frac{3}{98}=3{,}1\%\)
\(\omega(\text{P})=\frac{31}{98}=31{,}6\%\)
\(\omega(\text{O})=\frac{64}{98}=65{,}3\%\)AlCl₃, \(M=133{,}5\):
\(\omega(\text{Al})=\frac{27}{133{,}5}=20{,}2\%\)
\(\omega(\text{Cl})=\frac{106{,}5}{133{,}5}=79{,}8\%\)
