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Задача Задача №3762341
А
Аноним
5 дней назад · публичный вопрос
А
Аноним

Реши задание на изображении

Нейросеть5 дней назад

1.

  1. \(2^{1/2}\); 2) \(3^{-1/2}\); 3) \(2^{-3/2}\); 4) \(5^{2/3}\); 5) \(3^{3/4}\); 6) \(5^{-2/3}\).

2.

  1. \(\sqrt3\); 2) \(\frac1{2\sqrt2}\); 3) \(\sqrt[3]{25}\); 4) \(\sqrt[6]{3^5}\); 5) \(\sqrt[3]{(2/3)^{10}}\);
  2. \(\sqrt5\); 7) \(\frac1{\sqrt[4]2}\); 8) \(\sqrt[5]9\); 9) \(\sqrt{10}\); 10) \(\sqrt{\frac43}\).

3.

  1. \(2^{11/8}\);
  2. \(\left(\frac{2^2}{5^4}\right)^3=\frac{2^6}{5^{12}}\);
  3. \(3^{5/24}\);
  4. \(a^{17/6}\);
  5. \(a^{2/5}\);
  6. \(3^{-1/6}7^{1/3}\).

4.

  1. \(\frac12<2^{2/3}<2^{3/4}<2<2^{4/3}\);
  2. \(\left(\frac13\right)^2<9^{-1/3}<\left(\frac13\right)^{-1/2}<3^{3/4}<\left(\frac19\right)^{-3/2}\);
  3. \(\left(\frac9{25}\right)^2<\left(\frac34\right)^4<\left(-\frac34\right)^{-4}<2^4<(-3)^4\);
  4. \((-2)^3<\left(\frac23\right)^{-3}<3^3<2^6<\left(\frac1{27}\right)^{-2}\).

5.

  1. \(\left(\frac14\right)^{3/2}=\frac18>\frac19=\left(\frac1{27}\right)^{2/3}\);
  2. \(3^{1/3}>4^{1/4}>5^{1/5}\), так как \(3^4>4^3\) и \(4^5>5^4\);
  3. по неравенству Коши \(\sqrt{2003}+\sqrt{2005}<2\sqrt{2004}\);
  4. \(2^{1/100}>1\), поэтому \(2^{1/100}+10^{-1}>1\).

6.

  1. \(x=1\);
  2. \(x=1;\ -\frac34\);
  3. \(x=1\);
  4. \(x=-1;\ 2\);
  5. \(x=\frac13\);
  6. \(x=2\).
Реши задание на изображении
**1.** 1) \(2^{1/2}\); 2) \(3^{-1/2}\); 3) \(2^{-3/2}\); 4) \(5^{2/3}\); 5) \(3^{3/4}\); 6) \(5^{-2/3}\). **2.** 1) \(\sqrt3\); 2) \(\frac1{2\sqrt2}\); 3) \(\sqrt[3]{25}\); 4) \(\sqrt[6]{3^5}\); 5) \(\sqrt[3]{(2/3)^{10}}\); 6) \(\sqrt5\); 7) \(\frac1{\sqrt[4]2}\); 8) \(\sqrt[5]9\); 9) \(\sqrt{10}\); 10) \(\sqrt{\frac43}\). **3.** 1) \(2^{11/8}\); 2) \(\left(\frac{2^2}{5^4}\right)^3=\frac{2^6}{5^{12}}\); 3) \(3^{5/24}\); 4) \(a^{17/6}\); 5) \(a^{2/5}\); 6) \(3^{-1/6}7^{1/3}\). **4.** 1) \(\frac12<2^{2/3}<2^{3/4}<2<2^{4/3}\); 2) \(\left(\frac13\right)^2<9^{-1/3}<\left(\frac13\right)^{-1/2}<3^{3/4}<\left(\frac19\right)^{-3/2}\); 3) \(\left(\frac9{25}\right)^2<\left(\frac34\right)^4<\left(-\frac34\right)^{-4}<2^4<(-3)^4\); 4) \((-2)^3<\left(\frac23\right)^{-3}<3^3<2^6<\left(\frac1{27}\right)^{-2}\). **5.** 1) \(\left(\frac14\right)^{3/2}=\frac18>\frac19=\left(\frac1{27}\right)^{2/3}\); 2) \(3^{1/3}>4^{1/4}>5^{1/5}\), так как \(3^4>4^3\) и \(4^5>5^4\); 3) по неравенству Коши \(\sqrt{2003}+\sqrt{2005}<2\sqrt{2004}\); 4) \(2^{1/100}>1\), поэтому \(2^{1/100}+10^{-1}>1\). **6.** 1) \(x=1\); 2) \(x=1;\ -\frac34\); 3) \(x=1\); 4) \(x=-1;\ 2\); 5) \(x=\frac13\); 6) \(x=2\).