Задача Задача №3796133
А
А
Сверь числа и знаки с фото.
- \( \frac{6}{73}+4= \) | 2) \(5+2\frac{3}{14}=\) | 3) \(7\frac{3}{19}+\frac{16}{19}=\) | 4) \(12\frac{2}{3}+3=\)
- \(5\frac{8}{9}-3=\) | 6) \(6-\frac{3}{19}=\) | 7) \(7\frac{3}{8}-2\frac{1}{8}=\) | 8) \(13\frac{7}{17}-9\frac{13}{17}=\)
- \(1\frac{2}{25}-\frac{11}{25}=\) | 10) \(9\frac{7}{12}+\frac{1}{12}=\) | 11) \(7\frac{1}{8}+\frac{3}{8}=\) | 12) \(17\frac{9}{10}+50\frac{7}{10}=\)
- \(7\frac{5}{6}-1=\) | 14) \(10\frac{5}{14}-8\frac{3}{14}=\) | 15) \(12\frac{3}{10}-\frac{9}{10}=\) | 16) \(1-\frac{11}{14}=\)
- \(8\frac{10}{51}+\frac{7}{51}=\) | 18) \(\frac{21}{32}+\frac{19}{32}=\) | 19) \(8\frac{10}{51}+\frac{7}{51}=\) | 20) \(5\frac{4}{15}+13=\)
- \(12\frac{7}{11}-\frac{10}{11}=\) | 22) \(9\frac{1}{33}-\frac{4}{33}=\) | 23) \(8-3\frac{1}{12}=\) | 24) \(1-\frac{10}{23}=\)
- \(\frac{27}{28}+4\frac{9}{28}=\) | 26) \(3\frac{10}{13}+5\frac{11}{13}=\) | 27) \(7\frac{3}{10}+3\frac{7}{10}=\) | 28) \(31\frac{1}{9}+12\frac{8}{9}=\)
Ответы:
- \(4+\frac{6}{73}=4\frac{6}{73}\)
- \(5+2\frac{3}{14}=7\frac{3}{14}\)
- \(7\frac{3}{19}+\frac{16}{19}=8\)
- \(12\frac{2}{3}+3=15\frac{2}{3}\)
- \(5\frac{8}{9}-3=2\frac{8}{9}\)
- \(6-\frac{3}{19}=5\frac{16}{19}\)
- \(7\frac{3}{8}-2\frac{1}{8}=5\frac{1}{4}\)
- \(13\frac{7}{17}-9\frac{13}{17}=3\frac{11}{17}\)
- \(1\frac{2}{25}-\frac{11}{25}=\frac{16}{25}\)
- \(9\frac{7}{12}+\frac{1}{12}=9\frac{2}{3}\)
- \(7\frac{1}{8}+\frac{3}{8}=7\frac{1}{2}\)
- \(17\frac{9}{10}+50\frac{7}{10}=68\frac{3}{5}\)
- \(7\frac{5}{6}-1=6\frac{5}{6}\)
- \(10\frac{5}{14}-8\frac{3}{14}=2\frac{1}{7}\)
- \(12\frac{3}{10}-\frac{9}{10}=11\frac{2}{5}\)
- \(1-\frac{11}{14}=\frac{3}{14}\)
- \(8\frac{10}{51}+\frac{7}{51}=8\frac{1}{3}\)
- \(\frac{21}{32}+\frac{19}{32}=1\frac{1}{4}\)
- \(8\frac{10}{51}+\frac{7}{51}=8\frac{1}{3}\)
- \(5\frac{4}{15}+13=18\frac{4}{15}\)
- \(12\frac{7}{11}-\frac{10}{11}=11\frac{8}{11}\)
- \(9\frac{1}{33}-\frac{4}{33}=8\frac{10}{11}\)
- \(8-3\frac{1}{12}=4\frac{11}{12}\)
- \(1-\frac{10}{23}=\frac{13}{23}\)
- \(\frac{27}{28}+4\frac{9}{28}=5\frac{2}{7}\)
- \(3\frac{10}{13}+5\frac{11}{13}=9\frac{8}{13}\)
- \(7\frac{3}{10}+3\frac{7}{10}=11\)
- \(31\frac{1}{9}+12\frac{8}{9}=44\)