Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №3811694
А
Аноним
21 час назад · публичный вопрос
А
Аноним

Реши с решением

Ответ нейросети
21 час назад
  1. \(\frac{5}{6}\cdot\frac{5}{9}=\frac{25}{54}\)

  2. \(6\cdot4\frac{1}{3}=6\cdot\frac{13}{3}=26\)

  3. \(7\frac{1}{2}\cdot1\frac{5}{9}=\frac{15}{2}\cdot\frac{14}{9}=\frac{35}{3}=11\frac{2}{3}\)

  4. \(4\frac{6}{11}\cdot4\frac{2}{5}=\frac{50}{11}\cdot\frac{22}{5}=20\)

  5. \(6\frac{3}{4}\cdot1\frac{9}{39}=\frac{27}{4}\cdot\frac{48}{39}=\frac{108}{13}=8\frac{4}{13}\)

  6. \(\frac{11}{19}\cdot38=11\cdot2=22\)

  7. \(\frac{14}{55}\cdot1\frac{1}{21}=\frac{14}{55}\cdot\frac{22}{21}=\frac{4}{15}\)

  8. \(\frac{15}{28}\cdot1\frac{1}{6}=\frac{15}{28}\cdot\frac{7}{6}=\frac{5}{8}\)

  9. \(5\frac{3}{5}\cdot2\frac{13}{21}=\frac{28}{5}\cdot\frac{55}{21}=\frac{44}{3}=14\frac{2}{3}\)

  10. \(24\cdot3\frac{1}{4}=24\cdot\frac{13}{4}=78\)

  11. \(3\frac{1}{6}\cdot\frac{5}{19}=\frac{19}{6}\cdot\frac{5}{19}=\frac{5}{6}\)

  12. \(4\frac{1}{5}\cdot\frac{15}{49}=\frac{21}{5}\cdot\frac{15}{49}=\frac{9}{7}=1\frac{2}{7}\)

  13. \(2\frac{2}{11}\cdot\frac{5}{12}=\frac{24}{11}\cdot\frac{5}{12}=\frac{10}{11}\)

  14. \(1\frac{1}{3}\cdot1\frac{1}{2}=\frac{4}{3}\cdot\frac{3}{2}=2\)

  15. \(3\frac{1}{2}\cdot3\frac{1}{10}=\frac{7}{2}\cdot\frac{31}{10}=\frac{217}{20}=10\frac{17}{20}\)