Три цеха за смену изготовили 599 деталей. второй цех изготовил в два раза больше,чем первый,а третий-на 41 деталей меньше,чем второй. Сколько деталей изготовил каждый цех?

Hello!

Let's solve the problem step by step.

Let's assume the number of parts made by the first workshop is x.

The second workshop made twice as many parts as the first workshop. So, the number of parts made by the second workshop is 2x.

The third workshop made 41 parts less than the second workshop. So, the number of parts made by the third workshop is 2x - 41.

Adding up all the parts made by the three workshops, we have:

x + 2x + (2x - 41) = 599

Simplifying the equation, we get:

5x - 41 = 599

Now, we can solve for x:

5x = 599 + 41 5x = 640 x = 640/5 x = 128

So, the first workshop made 128 parts, the second workshop made 2x = 2 * 128 = 256 parts, and the third workshop made 2x - 41 = 2 * 128 - 41 = 215 parts.

Therefore, each workshop made the following number of parts:

• First workshop: 128 parts
• Second workshop: 256 parts
• Third workshop: 215 parts

I hope this helps! Let me know if you have any other questions.