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Задача Задача №38929
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Аноним
09 ноября 2023 12:13 · публичный вопрос
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Аноним

(-3-y)²

Нейросеть09 ноября 2023 12:13

To expand the expression \((-3-y)^2\), you square each term inside the parentheses and apply the distributive property (FOIL method for binomials) to account for the cross terms. Here's the step-by-step expansion:

\[ (-3 - y)^2 = (-3 - y) \cdot (-3 - y) \]

Applying the FOIL method, you multiply each term in the first binomial by each term in the second binomial:

  1. Multiply the first terms: \((-3) \cdot (-3) = 9\)
  2. Multiply the outer terms: \((-3) \cdot (-y) = 3y\)
  3. Multiply the inner terms: \((-y) \cdot (-3) = 3y\)
  4. Multiply the last terms: \((-y) \cdot (-y) = y^2\)

Add all these results together:

\[ 9 + 3y + 3y + y^2 \]

Combine like terms (the 3y terms):

\[ 9 + 6y + y^2 \]

It's common to write polynomial expressions in descending order of power, so the expanded form of \((-3 - y)^2\) in standard form is:

\[ y^2 + 6y + 9 \]

(-3-y)²
To expand the expression \((-3-y)^2\), you square each term inside the parentheses and apply the distributive property (FOIL method for binomials) to account for the cross terms. Here's the step-by-step expansion: \[ (-3 - y)^2 = (-3 - y) \cdot (-3 - y) \] Applying the FOIL method, you multiply each term in the first binomial by each term in the second binomial: 1. Multiply the first terms: \((-3) \cdot (-3) = 9\) 2. Multiply the outer terms: \((-3) \cdot (-y) = 3y\) 3. Multiply the inner terms: \((-y) \cdot (-3) = 3y\) 4. Multiply the last terms: \((-y) \cdot (-y) = y^2\) Add all these results together: \[ 9 + 3y + 3y + y^2 \] Combine like terms (the 3y terms): \[ 9 + 6y + y^2 \] It's common to write polynomial expressions in descending order of power, so the expanded form of \((-3 - y)^2\) in standard form is: \[ y^2 + 6y + 9 \]