6(a-b)–²

It looks like you have provided an expression with an exponent, but it's not entirely clear from the text what the exact expression is. I'll interpret "6(a-b)–²" as "6(a - b)^-2", which implies you want to take the expression (a - b) to the power of -2, and then multiply the result by 6.

Here's how you can simplify or expand that expression:

The negative exponent ^-2 means that you will take the reciprocal of the base and square it. In other words, (a - b)^-2 is equivalent to 1/(a - b)^2.

So when you multiply by 6, the expression becomes:

6 * (a - b)^-2 =

6 * 1/(a - b)^2 =

6/(a - b)^2

This is the simplified form of the expression.

If you need to expand (a - b)^2, it would be (a - b)(a - b) which equals a^2 - 2ab + b^2. Then, the expression 6/(a - b)^2 would remain in its simplified fractional form, because we typically leave expressions in terms of the smallest possible components when simplifying. If you wanted to incorporate the 6 into the expanded form for some reason, you would multiply each term by 6:

6/(a^2 - 2ab + b^2)

Keep in mind without any additional context, the expression 6/(a - b)^2 is already in a simplified form. If this does not answer your question, please provide additional information.