Дано множество M ={4,1,3,2,5,8,6,7,10,15}. C={xlxэ M и xł9} B={xlxэ M и 45÷x

The set C contains elements x such that x is an element of M and x is a divisor of 9. The symbol "ł" is assumed to be "divides". In mathematical notation, C can be written as:

C = {x | x ∈ M and x | 9}

Looking at the given set M = {4,1,3,2,5,8,6,7,10,15}, we have to find the numbers that divide 9:

• 1 divides 9
• 3 divides 9

All other numbers in M do not divide 9. So, the set C is:

C = {1, 3}

The set B contains elements x such that x is an element of M and 45 is divisible by x. In mathematical notation, B can be written as:

B = {x | x ∈ M and 45 ÷ x}

Let's find the elements of M that are divisors of 45:

• 1 divides 45 (45 ÷ 1 = 45)
• 3 divides 45 (45 ÷ 3 = 15)
• 5 divides 45 (45 ÷ 5 = 9)
• 15 divides 45 (45 ÷ 15 = 3)

These are all the divisors of 45 that are in set M. Thus, the set B is:

B = {1, 3, 5, 15}