Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №49491
А
Аноним
20 ноября 2023 04:59 · публичный вопрос
А
Аноним

X+y=5 3x+y=7

Нейросеть20 ноября 2023 04:59

The system of linear equations you've provided consists of two equations:

  1. x + y = 5
  2. 3x + y = 7

To solve this system, we can use either the substitution method or the elimination method. Here, the elimination method seems straightforward since both equations have the variable y with the same coefficient. Let's subtract the first equation from the second equation to eliminate y.

Subtract equation 1 from equation 2: (3x + y) - (x + y) = 7 - 5

Solve for x: 3x + y - x - y = 2 3x - x = 2 2x = 2 x = 2/2 x = 1

Now that we know the value of x, we can use it to solve for y by substituting x into either of the original equations. Let's use the first equation:

x + y = 5 1 + y = 5 y = 5 - 1 y = 4

Thus, the solution to the system of equations is x = 1 and y = 4.

x+y=5 3x+y=7
The system of linear equations you've provided consists of two equations: 1) x + y = 5 2) 3x + y = 7 To solve this system, we can use either the substitution method or the elimination method. Here, the elimination method seems straightforward since both equations have the variable y with the same coefficient. Let's subtract the first equation from the second equation to eliminate y. Subtract equation 1 from equation 2: (3x + y) - (x + y) = 7 - 5 Solve for x: 3x + y - x - y = 2 3x - x = 2 2x = 2 x = 2/2 x = 1 Now that we know the value of x, we can use it to solve for y by substituting x into either of the original equations. Let's use the first equation: x + y = 5 1 + y = 5 y = 5 - 1 y = 4 Thus, the solution to the system of equations is x = 1 and y = 4.