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Задача Задача №49496
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20 ноября 2023 05:43 · публичный вопрос
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X+y=5 3x+y=7

Нейросеть20 ноября 2023 05:43

You've provided a system of two linear equations with two variables, x and y. To find the solution for x and y, you can use either the substitution method or the elimination method. Let's solve it using the elimination method:

Equation (1) is: x + y = 5 Equation (2) is: 3x + y = 7

Now, you need to eliminate one of the variables. Let's eliminate y.

First, align the equations: x + y = 5 (1) 3x + y = 7 (2)

Now, subtract equation (1) from equation (2) to eliminate y: (3x + y) - (x + y) = (7) - (5)

This simplifies to: 3x + y - x - y = 2 2x = 2

Divide both sides by 2 to solve for x: x = 2/2 x = 1

Now that we have the value for x, we can substitute it back into either equation (1) or (2) to solve for y. Let's use equation (1):

x + y = 5 1 + y = 5 (substituting x = 1)

Now solve for y: y = 5 - 1 y = 4

So the solution to the system of equations is: x = 1 y = 4

x+y=5 3x+y=7
You've provided a system of two linear equations with two variables, x and y. To find the solution for x and y, you can use either the substitution method or the elimination method. Let's solve it using the elimination method: Equation (1) is: x + y = 5 Equation (2) is: 3x + y = 7 Now, you need to eliminate one of the variables. Let's eliminate y. First, align the equations: x + y = 5 (1) 3x + y = 7 (2) Now, subtract equation (1) from equation (2) to eliminate y: (3x + y) - (x + y) = (7) - (5) This simplifies to: 3x + y - x - y = 2 2x = 2 Divide both sides by 2 to solve for x: x = 2/2 x = 1 Now that we have the value for x, we can substitute it back into either equation (1) or (2) to solve for y. Let's use equation (1): x + y = 5 1 + y = 5 (substituting x = 1) Now solve for y: y = 5 - 1 y = 4 So the solution to the system of equations is: x = 1 y = 4