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Задача Задача №514607
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Аноним
27 февраля 2024 04:27 · публичный вопрос
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Аноним

(5-а)(5+а)(25+а)в квадрате

Нейросеть27 февраля 2024 04:27

To simplify the expression \((5-a)(5+a)(25+a)\) and then square the result, we will first expand the product of the three terms:

\((5-a)(5+a)(25+a) = (25 - a^2)(25 + a) = 625 + 25a - 25a - a^2 • a = 625 - a^3\)

Now, to square the result, we will square the expression \((625 - a^3)\):

\((625 - a^3)^2 = 625^2 - 2 • 625 • a^3 + a^6\)

Finally, we simplify the expression further:

\(625^2 = 390625\)

\(-2 • 625 • a^3 = -1250a^3\)

\(a^6 = a^6\)

Therefore, the final result after squaring the given expression is:

\(390625 - 1250a^3 + a^6\)

(5-а)(5+а)(25+а)в квадрате
To simplify the expression \((5-a)(5+a)(25+a)\) and then square the result, we will first expand the product of the three terms: \((5-a)(5+a)(25+a) = (25 - a^2)(25 + a) = 625 + 25a - 25a - a^2 • a = 625 - a^3\) Now, to square the result, we will square the expression \((625 - a^3)\): \((625 - a^3)^2 = 625^2 - 2 • 625 • a^3 + a^6\) Finally, we simplify the expression further: \(625^2 = 390625\) \(-2 • 625 • a^3 = -1250a^3\) \(a^6 = a^6\) Therefore, the final result after squaring the given expression is: \(390625 - 1250a^3 + a^6\)